VB编写的,你看看呢? 叶轮几何尺寸计算 Clarkx(1) = 0: Clarkx(2) = 1.25: Clarkx(3) = 2.5: Clarkx(4) = 5: Clarkx(5) = 7.5: Clarkx(6) = 10: Clarkx(7) = 15 Clarkx(8) = 20: Clarkx(9) = 30: Clarkx(10) = 40: Clarkx(11) = 50: Clarkx(12) = 60: Clarkx(13) = 70: Clarkx(14) = 80 Clarkx(15) = 90: Clarkx(16) = 95: Clarkx(17) = 100 Clarky(1, 1) = 2.99: Clarky(1, 2) = 4.66: Clarky(1, 3) = 5.56: Clarky(1, 4) = 6.75: Clarky(1, 5) = 7.56 Clarky(1, 6) = 8.2: Clarky(1, 7) = 9.14: Clarky(1, 8) = 9.72: Clarky(1, 9) = 10: Clarky(1, 10) = 9.75 Clarky(1, 11) = 9: Clarky(1, 12) = 7.82: Clarky(1, 13) = 6.28: Clarky(1, 14) = 4.46: Clarky(1, 15) = 2.39 Clarky(1, 16) = 1.27: Clarky(1, 17) = 0.1 Clarky(2, 1) = 2.99: Clarky(2, 2) = 1.65: Clarky(2, 3) = 1.26: Clarky(2, 4) = 0.8: Clarky(2, 5) = 0.54 Clarky(2, 6) = 0.36: Clarky(2, 7) = 0.13: Clarky(2, 8) = 0.03: Clarky(2, 9) = 0: Clarky(2, 10) = 0 Clarky(2, 11) = 0: Clarky(2, 12) = 0: Clarky(2, 13) = 0: Clarky(2, 14) = 0: Clarky(2, 15) = 0: Clarky(2, 16) = 0 Clarky(2, 17) = 0 Ls(1, 1) = 0.05: Ls(1, 2) = 0.1: Ls(1, 3) = 0.2: Ls(1, 4) = 0.3: Ls(1, 5) = 0.4: Ls(1, 6) = 0.5: Ls(1, 7) = 0.6 Ls(1, 8) = 0.7: Ls(1, 9) = 0.8: Ls(1, 10) = 0.9: Ls(1, 11) = 0.12 Ls(2, 1) = 0.592: Ls(2, 2) = 0.786: Ls(2, 3) = 0.961: Ls(2, 4) = 1: Ls(2, 5) = 0.991 Ls(2, 6) = 0.961: Ls(2, 7) = 0.873 Ls(2, 8) = 0.747: Ls(2, 9) = 0.572: Ls(2, 10) = 0.369: Ls(2, 11) = 0.09
计算弦长b在叶栅额叶及轴线方向的投影 Dim i As Integer Dim j As Integer
For j = 1 To 7 B(1, j) = A(13, j) * Cos(A(12, j) * Pi / 180) List2(j - 1).AddItem B(1, j) B(2, j) = A(13, j) * Sin(A(12, j) * Pi / 180) List2(j - 1).AddItem B(2, j) 重心坐标 B(3, j) = 0.445 * A(13, j) List2(j - 1).AddItem B(3, j) B(4, j) = 0 List2(j - 1).AddItem B(4, j) B(5, j) = B(3, j) * Sin(A(12, j) * Pi / 180) List2(j - 1).AddItem B(5, j) B(6, j) = B(3, j) * Cos(A(12, j) * Pi / 180) List2(j - 1).AddItem B(6, j)
B(7, j) = (A(13, j) - B(3, j)) * Sin(A(12, j) * Pi / 180) List2(j - 1).AddItem B(7, j) B(8, j) = (A(13, j) - B(3, j)) * Cos(A(12, j) * Pi / 180) List2(j - 1).AddItem B(8, j) Next j 坐标 For i = 1 To 7 For j = 1 To 17
cx(i, j) = A(13, i) * Clarkx(j) / 100 cy1(i, j) = A(13, i) * Clarky(1, j) / 100 * C(i) cy2(i, j) = A(13, i) * Clarky(2, j) / 100 * C(i) Next j Next i
End Sub
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